If where is prime, then is abelian.
Proof:
We know is a normal subgroup, meaning its order divides , meaning it's either 1, , or .
If , then , meaning is abelian.
If , then , meaning is cyclic by TheoremTheorem, meaning is abelian. Note that since is abelian, , so this case doesn't even happen.
If , the Class equationClass equation gives that where we know each is either , or , and since they are all greater than (since only the orbits of elements of have size ), it's either or . This means the right hand side is divisible by , but clearly the left hand side isn't, meaning .